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The property outputs a GUID, if it is not null, but from that GUID, how can I get a filename?
Please refer here for property page: http://producthelp.sdl.com/SDK/ProjectAutomationApi/3.0/html/0597a5f6-ad63-7c89-01ad-27e846158bcb.htm
The property outputs a GUID, if it is not null, but from that GUID, how can I get a filename?
Please refer here for property page: http://producthelp.sdl.com/SDK/ProjectAutomationApi/3.0/html/0597a5f6-ad63-7c89-01ad-27e846158bcb.htm
This question might be very basic, but I still can't figure this out.
Can some one please help me figure out how I can get a name of the file that is generating a message via ExecutionMessage.ProjectFileId?
You can use GetFile method from FileBasedProject class. This method has a Guid parameter where you can specify ProjectFieldId value. The returned value its a ProjectFile which has a property Name which store the name of the file.
Hope this helps.
Romulus Crisan | Translation Productivity Development Manager | SDL | (twitter) @cromica_82 | (blog) http://www.romuluscrisan.com/
You can use GetFile method from FileBasedProject class. This method has a Guid parameter where you can specify ProjectFieldId value. The returned value its a ProjectFile which has a property Name which store the name of the file.
Hope this helps.
Romulus Crisan | Translation Productivity Development Manager | SDL | (twitter) @cromica_82 | (blog) http://www.romuluscrisan.com/
