Python parser

Question

I want to create a Python text parser. All texts in quotation marks should be found. This is quite simple in Passolo as a text parser, by setting " as the beginning and end connoisseur. But the problem is caused by escaped characters. If there is a quotation mark in the text, then write \". If you want to display a backslash \. This is searched in paths and is often placed at the end of the string, directly before the closing quotation mark: So I need a parser that can also parse the text. 
 print ( "c:\test\" + "this is a \"test\"" ) 
 The parser should then return two texts: 
 c:\test\ and this is a \"test\" Any ideas? Thanks Winfried

Naoko Jones · Accepted Answer

OK I tested for those: 
 print ("c:\test\" + "this is a \"test\"") print ("test" + "this is a test") 
 and this works: 
 ((?<!("|\))|(?<=(\\|\")))" 
 
 It's Monday morning for me, so I am not sure if this is good enough, but it should work for both Start and End expressions. 
 Thanks, 
 Naoko

Achim Herrmann · Answer

I can offer a much simpler solution that works without regular expressions. Simply use the quotes to look for strings and introduce a some mappings for the known escape sequences. 
 
 This will also convert (and reconvert) the known escape sequences into the real characters for translators.

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Python parser

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