Can't test it now, but I think that it should work if you change

the source regex to:

[A-Z]\((\W)\)

and the target regex to:

$1

The source regex still needs the unescaped parentheses to set the group and then backreference it with number $1 in the target regex (although $0 might work as well…).

Hi Jésus,

Thanks for the quick reply. I tried your suggestion, and it worked in part: it correctly flags up a missing (+) or (-) in the target. However, it doesn't spot an incorrect letter, because (if I understand correctly) the $1 only captures and checks for the part in brackets.

I thought $0 meant "capture all of the source expression", so I tried putting that in the target box, but that flagged up every matching pattern in the source as "missing" in the target, even though they were all present and correct.
I then tried ([A-Z])\((\W)\) as the source, and $1$2 as the target, but that did the same: flagged everything as missing even when it was present.

I suppose I could set up a second, separate, grouped Regex to check single capital letters, but if there's something that can combine the two, that would be better!

So I'm still searching...

Hayley

OK, if you also need to check the character before the parentheses, then this source regex should work:

([A-Z])(\(\W\))

with the target regex you mentioned:

$1$2

Thanks again for your help! For info/for anyone else reading this, I posted the same question in another forum, and somebody there suggested an alternative version, which also works:

Source: ([A-Z]\([\+-]\))

Target: $0

Yeah, there are usually several regexes.

I even think your latest regex can be simplified to

([A-Z]\([+-]\)) with the same target regex,

and even to:

[A-Z]\([+-]\)

and don't use a grouped regex at all.

Yeah, there are usually several regexes.

I even think your latest regex can be simplified to

([A-Z]\([+-]\)) with the same target regex,

and even to:

[A-Z]\([+-]\)

and don't use a grouped regex at all.