Renato Colonna Rosman

You could use something like this:

Search for:

\d(?=(?:\d{3})+(?!\d))

Replace with:

$0,

Dear Paul

Thank you very much for your kind attention, but the regular expression did not work in Trados Studio 2021 SR2 - 16.2.10.9305.

I selected, for example, the Target Segment containing only 16825.

Then I inserted the expression \d(?=(?:\d{3})+(?!\d)) in "Find What",

then I inserted the expression $0. (because I want to insert thousand dot separator) in "Replace with",

then I selected "Look in" (Selection), then I chose "use" Regular expressions",

when I click on "Find Next", the cursor selects the number "[6]",

when I click on "Replace", I read the answer: "Find complete: no matches found". No thousand separator is inserted. I other words, the number 16825 is not modified to 16.825, it remains as 16825.

The correct Regular Expressions for Trados Studio should be related to ".NET implementation". I have tested several Regular expressions (.NET implementation) in order to insert one or more thousand separators (as dot (.)) in numbers, but without any success.

Best regards

Renato Colonna Rosman

Renato Colonna Rosman said:

Thank you very much for the solution using the SDLXLIFF Toolkit!

You're welcome.  A big advantage here is you can do all the files in your project in one go with this plugin and because it's only regex it's easy to adapt as needed to suit what's in your actual document.

Dear Paul

The solution using the SDLXLIFF toolkit, as you explained in your Video, is good in order to insert thousand separators (using regex) in each number equal to or greater than 1000 on each Target Segment, including year numbers and reference document page numbers.

Is there a means to insert thousand separator only on some selected Target Segments containing only numbers equal to or greater than 1000 from a Table relating to numerical measured values?

I wait for your answer as soon as possible.

Thank you very much for your kind attention.

Best regards.

I have made it.
It is a Paid service.

could be made in version2021 too, currently version2017

- psst, I have read your comment as "more than 1000" mistakenly.

Hi Renato Colonna Rosman,

You can simply run the below replacement several times to achieve what you want:
Find what: (\d)(\d{3})\b
Replace with: $1.$2
It works even with numbers preceded or followed by anything else (e.g., "Only 1000 $", "My 1235567980 rubles", "34589 any text").
In your case, you have to run the replacement 3 times to cover all segments.
======
Also, you can use Regex Match AutoSuggest Provider (from RWS appstore) to get suggestions on the go:

======
Also, if you use AHK, you can ask for a script at the RWS AHK forum (if you think 3 clicks are too much ).

it does not work

Kelly Edward said:

it does not work

It does. Try reading the original post and examples.
You just suggest a different case and scenario. Cases can be different, right. But my solution works fine for the original case. If the original poster had anything different like 1234Times, they would put it straight in the list of examples. 
When a different case arises, I will suggest a different solution.

testing is testing.. never mind

Good Luck To You

Kelly Edward said:

another testing

Another scenario you mean? Right, this is another scenario. Has nothing to do with the original inquiry.

I have tested mine too.
In above both cases, it never worked out too.

Regards

The regex works as designed: place a period before a series of 3-digits preceded by a digit and not followed by a digit. 1234 

The regex works as designed: place a period before a series of 3-digits preceded by a digit and not followed by a digit. 1234